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-2z^2-15z^2+z^2=0
We add all the numbers together, and all the variables
-16z^2=0
a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{-32}=0$
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